(4/5)^15=(4/5)^2x+1

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Solution for (4/5)^15=(4/5)^2x+1 equation: 



(4/5)^15=(4/5)^2x+1

We move all terms to the left:

(4/5)^15-((4/5)^2x+1)=0



Domain of the equation: 5)^2x+1)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+4/5)^2x+1)+(+4/5)^15=0

We calculate fractions


()/5^2x+1)*5)^15)+20^2x/5^2x+1)*5)^15)=0

We calculate fractions

We do not support expression: x^4

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